re4-unvm-me

攻防世界-re4-unvm-me

下载文件为pyc文件，通过uncompyle6将其反编译为py文件，其中uncompyle6支持python2.6-3.8

文件代码如下

# uncompyle6 version 3.7.4
# Python bytecode 2.7 (62211)
# Decompiled from: Python 3.7.9 (tags/v3.7.9:13c94747c7, Aug 17 2020, 18:58:18) [MSC v.1900 64 bit (AMD64)]
# Embedded file name: unvm_me.py
# Compiled at: 2016-12-21 05:44:01
import md5
md5s = [
 174282896860968005525213562254350376167, 137092044126081477479435678296496849608, 126300127609096051658061491018211963916, 314989972419727999226545215739316729360, 256525866025901597224592941642385934114, 115141138810151571209618282728408211053, 8705973470942652577929336993839061582, 256697681645515528548061291580728800189, 39818552652170274340851144295913091599, 65313561977812018046200997898904313350, 230909080238053318105407334248228870753, 196125799557195268866757688147870815374, 74874145132345503095307276614727915885]
print 'Can you turn me back to python ? ...'
flag = raw_input('well as you wish.. what is the flag: ')
if len(flag) > 69:
    print 'nice try'
    exit()
if len(flag) % 5 != 0:
    print 'nice try'
    exit()
for i in range(0, len(flag), 5):
    s = flag[i:i + 5]
    if int('0x' + md5.new(s).hexdigest(), 16) != md5s[(i / 5)]:
        print 'nice try'
        exit()

print 'Congratz now you have the flag'

将md5s中的挨个解密即得flag

在线解密网站

md5解密 MD5在线解密 破解md5 (pmd5.com) //免费

md5在线解密破解,md5解密加密 (cmd5.com) //部分收费

最终求得flag

ALEXCTF{dv5d4s2vj8nk43s8d8l6m1n5l67ds9v41n52nv37j481h3d28n4b6v3k}